Base | Representation |
---|---|
bin | 11101110010110… |
… | …100011100111101 |
3 | 1021211120120210211 |
4 | 131302310130331 |
5 | 2010431030214 |
6 | 121333432421 |
7 | 15246515413 |
oct | 3562643475 |
9 | 1254516724 |
10 | 499861309 |
11 | 237182222 |
12 | 11b49b711 |
13 | 7c736c2c |
14 | 4a55b2b3 |
15 | 2dd3c0c4 |
hex | 1dcb473d |
499861309 has 4 divisors (see below), whose sum is σ = 510496704. Its totient is φ = 489225916.
The previous prime is 499861303. The next prime is 499861331. The reversal of 499861309 is 903168994.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 499861309 - 215 = 499828541 is a prime.
It is a super-2 number, since 2×4998613092 = 499722656470386962, which contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (499861303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5317627 + ... + 5317720.
It is an arithmetic number, because the mean of its divisors is an integer number (127624176).
Almost surely, 2499861309 is an apocalyptic number.
It is an amenable number.
499861309 is a deficient number, since it is larger than the sum of its proper divisors (10635395).
499861309 is a wasteful number, since it uses less digits than its factorization.
499861309 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10635394.
The product of its (nonzero) digits is 419904, while the sum is 49.
The square root of 499861309 is about 22357.5783348734. The cubic root of 499861309 is about 793.6271331180.
The spelling of 499861309 in words is "four hundred ninety-nine million, eight hundred sixty-one thousand, three hundred nine".
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