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4999120003 is a prime number
BaseRepresentation
bin1001010011111100…
…01000010010000011
3110220101201121102201
410221332020102003
540214233320003
62144020254031
7234611550613
oct45176102203
913811647381
104999120003
112135966939
12b76241317
13618911197
14355d12a43
151e3d30b1d
hex129f88483

4999120003 has 2 divisors, whose sum is σ = 4999120004. Its totient is φ = 4999120002.

The previous prime is 4999119959. The next prime is 4999120013. The reversal of 4999120003 is 3000219994.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4999120003 - 29 = 4999119491 is a prime.

It is not a weakly prime, because it can be changed into another prime (4999120013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2499560001 + 2499560002.

It is an arithmetic number, because the mean of its divisors is an integer number (2499560002).

Almost surely, 24999120003 is an apocalyptic number.

4999120003 is a deficient number, since it is larger than the sum of its proper divisors (1).

4999120003 is an equidigital number, since it uses as much as digits as its factorization.

4999120003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 37.

The square root of 4999120003 is about 70704.4553263795. The cubic root of 4999120003 is about 1709.8756225439.

Adding to 4999120003 its reverse (3000219994), we get a palindrome (7999339997).

The spelling of 4999120003 in words is "four billion, nine hundred ninety-nine million, one hundred twenty thousand, three".