Base | Representation |
---|---|
bin | 101110100100010000… |
… | …111110111001001001 |
3 | 11210001121212101202101 |
4 | 232210100332321021 |
5 | 1304400120234333 |
6 | 34545301233401 |
7 | 3420026465362 |
oct | 564420767111 |
9 | 153047771671 |
10 | 50000555593 |
11 | 1a22901251a |
12 | 9835102861 |
13 | 493ac05891 |
14 | 25c4836b69 |
15 | 147995467d |
hex | ba443ee49 |
50000555593 has 2 divisors, whose sum is σ = 50000555594. Its totient is φ = 50000555592.
The previous prime is 50000555573. The next prime is 50000555597. The reversal of 50000555593 is 39555500005.
50000555593 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49903985664 + 96569929 = 223392^2 + 9827^2 .
It is a cyclic number.
It is not a de Polignac number, because 50000555593 - 217 = 50000424521 is a prime.
It is not a weakly prime, because it can be changed into another prime (50000555597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25000277796 + 25000277797.
It is an arithmetic number, because the mean of its divisors is an integer number (25000277797).
Almost surely, 250000555593 is an apocalyptic number.
It is an amenable number.
50000555593 is a deficient number, since it is larger than the sum of its proper divisors (1).
50000555593 is an equidigital number, since it uses as much as digits as its factorization.
50000555593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84375, while the sum is 37.
The spelling of 50000555593 in words is "fifty billion, five hundred fifty-five thousand, five hundred ninety-three".
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