Base | Representation |
---|---|
bin | 101110100100010101… |
… | …001001110111000011 |
3 | 11210001200220221202022 |
4 | 232210111021313003 |
5 | 1304400410232331 |
6 | 34545340512055 |
7 | 3420042001412 |
oct | 564425116703 |
9 | 153050827668 |
10 | 50001649091 |
11 | 1a22969a039 |
12 | 983554b62b |
13 | 493b1c9514 |
14 | 25c4a3d479 |
15 | 1479abd67b |
hex | ba4549dc3 |
50001649091 has 2 divisors, whose sum is σ = 50001649092. Its totient is φ = 50001649090.
The previous prime is 50001648979. The next prime is 50001649123. The reversal of 50001649091 is 19094610005.
50001649091 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50001649091 is a prime.
It is a super-2 number, since 2×500016490912 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50001649591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25000824545 + 25000824546.
It is an arithmetic number, because the mean of its divisors is an integer number (25000824546).
Almost surely, 250001649091 is an apocalyptic number.
50001649091 is a deficient number, since it is larger than the sum of its proper divisors (1).
50001649091 is an equidigital number, since it uses as much as digits as its factorization.
50001649091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 35.
The spelling of 50001649091 in words is "fifty billion, one million, six hundred forty-nine thousand, ninety-one".
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