Base | Representation |
---|---|
bin | 10110101111010111011011… |
… | …10111111001000111110001 |
3 | 20120001112020010102112121102 |
4 | 23113223231313321013301 |
5 | 23023244242012041423 |
6 | 254204234520334145 |
7 | 13350546204504263 |
oct | 1327535567710761 |
9 | 216045203375542 |
10 | 50006000112113 |
11 | 14a2a475456131 |
12 | 57375b8314355 |
13 | 21b971282aa86 |
14 | c4c436445b33 |
15 | 5bab867bac28 |
hex | 2d7aeddf91f1 |
50006000112113 has 2 divisors, whose sum is σ = 50006000112114. Its totient is φ = 50006000112112.
The previous prime is 50006000112073. The next prime is 50006000112119. The reversal of 50006000112113 is 31121100060005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45024207360064 + 4981792752049 = 6710008^2 + 2231993^2 .
It is a cyclic number.
It is not a de Polignac number, because 50006000112113 - 216 = 50006000046577 is a prime.
It is not a weakly prime, because it can be changed into another prime (50006000112119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25003000056056 + 25003000056057.
It is an arithmetic number, because the mean of its divisors is an integer number (25003000056057).
Almost surely, 250006000112113 is an apocalyptic number.
It is an amenable number.
50006000112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
50006000112113 is an equidigital number, since it uses as much as digits as its factorization.
50006000112113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 50006000112113 its reverse (31121100060005), we get a palindrome (81127100172118).
The spelling of 50006000112113 in words is "fifty trillion, six billion, one hundred twelve thousand, one hundred thirteen".
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