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50009101434881 is a prime number
BaseRepresentation
bin10110101111011101001101…
…01110100000000000000001
320120001211020021010001122122
423113232212232200000001
523023322114431404011
6254205510344414025
713351016103351521
oct1327564656400001
9216054207101578
1050009101434881
1114a308170308a6
125738122a77315
1321b9ab81c9bc4
14c4c64c2a5681
155bacb8bc63db
hex2d7ba6ba0001

50009101434881 has 2 divisors, whose sum is σ = 50009101434882. Its totient is φ = 50009101434880.

The previous prime is 50009101434869. The next prime is 50009101434907. The reversal of 50009101434881 is 18843410190005.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30244995207025 + 19764106227856 = 5499545^2 + 4445684^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50009101434881 is a prime.

It is a super-3 number, since 3×500091014348813 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (50009101434821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25004550717440 + 25004550717441.

It is an arithmetic number, because the mean of its divisors is an integer number (25004550717441).

Almost surely, 250009101434881 is an apocalyptic number.

It is an amenable number.

50009101434881 is a deficient number, since it is larger than the sum of its proper divisors (1).

50009101434881 is an equidigital number, since it uses as much as digits as its factorization.

50009101434881 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 138240, while the sum is 44.

The spelling of 50009101434881 in words is "fifty trillion, nine billion, one hundred one million, four hundred thirty-four thousand, eight hundred eighty-one".