Base | Representation |
---|---|
bin | 10110101111100001011100… |
… | …00111000111111010011011 |
3 | 20120002001002120010002000102 |
4 | 23113300232013013322123 |
5 | 23023341242420021404 |
6 | 254210524004130015 |
7 | 13351126303640153 |
oct | 1327605607077233 |
9 | 216061076102012 |
10 | 50011372813979 |
11 | 14a31782183605 |
12 | 573865769690b |
13 | 21ba08a9609c5 |
14 | c4c7c5c03763 |
15 | 5bad9d2e271e |
hex | 2d7c2e1c7e9b |
50011372813979 has 2 divisors, whose sum is σ = 50011372813980. Its totient is φ = 50011372813978.
The previous prime is 50011372813951. The next prime is 50011372814107. The reversal of 50011372813979 is 97931827311005.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50011372813979 - 232 = 50007077846683 is a prime.
It is a super-3 number, since 3×500113728139793 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (50011372813679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25005686406989 + 25005686406990.
It is an arithmetic number, because the mean of its divisors is an integer number (25005686406990).
Almost surely, 250011372813979 is an apocalyptic number.
50011372813979 is a deficient number, since it is larger than the sum of its proper divisors (1).
50011372813979 is an equidigital number, since it uses as much as digits as its factorization.
50011372813979 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2857680, while the sum is 56.
The spelling of 50011372813979 in words is "fifty trillion, eleven billion, three hundred seventy-two million, eight hundred thirteen thousand, nine hundred seventy-nine".
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