50011516433 has 2 divisors, whose sum is σ = 50011516434. Its totient is φ = 50011516432.

The previous prime is 50011516417. The next prime is 50011516517. The reversal of 50011516433 is 33461511005.

50011516433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49971472849 + 40043584 = 223543^2 + 6328^2 .

It is a cyclic number.

It is not a de Polignac number, because 50011516433 - 2⁴ = 50011516417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50011516396 and 50011516405.

It is not a weakly prime, because it can be changed into another prime (50011519433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25005758216 + 25005758217.

It is an arithmetic number, because the mean of its divisors is an integer number (25005758217).

Almost surely, 2^50011516433 is an apocalyptic number.

It is an amenable number.

50011516433 is a deficient number, since it is larger than the sum of its proper divisors (1).

50011516433 is an equidigital number, since it uses as much as digits as its factorization.

50011516433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 29.

The spelling of 50011516433 in words is "fifty billion, eleven million, five hundred sixteen thousand, four hundred thirty-three".