Base | Representation |
---|---|
bin | 101110100101001100… |
… | …010011000000101011 |
3 | 11210002201010100211111 |
4 | 232211030103000223 |
5 | 1304413110320431 |
6 | 34551014411151 |
7 | 3420305605423 |
oct | 564514230053 |
9 | 153081110744 |
10 | 50016104491 |
11 | 1a236872651 |
12 | 983a360ab7 |
13 | 49411bb002 |
14 | 25c6923483 |
15 | 147aec67b1 |
hex | ba531302b |
50016104491 has 2 divisors, whose sum is σ = 50016104492. Its totient is φ = 50016104490.
The previous prime is 50016104477. The next prime is 50016104587. The reversal of 50016104491 is 19440161005.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50016104491 - 217 = 50015973419 is a prime.
It is a super-2 number, since 2×500161044912 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50016104461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25008052245 + 25008052246.
It is an arithmetic number, because the mean of its divisors is an integer number (25008052246).
Almost surely, 250016104491 is an apocalyptic number.
50016104491 is a deficient number, since it is larger than the sum of its proper divisors (1).
50016104491 is an equidigital number, since it uses as much as digits as its factorization.
50016104491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
Adding to 50016104491 its reverse (19440161005), we get a palindrome (69456265496).
The spelling of 50016104491 in words is "fifty billion, sixteen million, one hundred four thousand, four hundred ninety-one".
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