Base | Representation |
---|---|
bin | 10110110000001000101001… |
… | …11100011111110011011111 |
3 | 20120011001102202022222221021 |
4 | 23120010110330133303133 |
5 | 23024212401402344320 |
6 | 254224325014545011 |
7 | 13352503100155111 |
oct | 1330042474376337 |
9 | 216131382288837 |
10 | 50032425434335 |
11 | 14a3a6a58a6903 |
12 | 5740752068167 |
13 | 21bc06443a806 |
14 | c4d821c133b1 |
15 | 5bb6d1685daa |
hex | 2d8114f1fcdf |
50032425434335 has 4 divisors (see below), whose sum is σ = 60038910521208. Its totient is φ = 40025940347464.
The previous prime is 50032425434227. The next prime is 50032425434347. The reversal of 50032425434335 is 53343452423005.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50032425434335 - 213 = 50032425426143 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50032425434291 and 50032425434300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5003242543429 + ... + 5003242543438.
It is an arithmetic number, because the mean of its divisors is an integer number (15009727630302).
Almost surely, 250032425434335 is an apocalyptic number.
50032425434335 is a deficient number, since it is larger than the sum of its proper divisors (10006485086873).
50032425434335 is a wasteful number, since it uses less digits than its factorization.
50032425434335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10006485086872.
The product of its (nonzero) digits is 2592000, while the sum is 43.
The spelling of 50032425434335 in words is "fifty trillion, thirty-two billion, four hundred twenty-five million, four hundred thirty-four thousand, three hundred thirty-five".
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