Base | Representation |
---|---|
bin | 101110100110101000… |
… | …101000001000111001 |
3 | 11210011101200001012011 |
4 | 232212220220020321 |
5 | 1304440304331111 |
6 | 34553241245521 |
7 | 3421021413415 |
oct | 564650501071 |
9 | 153141601164 |
10 | 50040308281 |
11 | 1a2494a4287 |
12 | 98464938a1 |
13 | 4946213992 |
14 | 25c9c23d45 |
15 | 147d1a8021 |
hex | ba6a28239 |
50040308281 has 2 divisors, whose sum is σ = 50040308282. Its totient is φ = 50040308280.
The previous prime is 50040308237. The next prime is 50040308287. The reversal of 50040308281 is 18280304005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49721864256 + 318444025 = 222984^2 + 17845^2 .
It is a cyclic number.
It is not a de Polignac number, because 50040308281 - 223 = 50031919673 is a prime.
It is a super-2 number, since 2×500403082812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50040308287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25020154140 + 25020154141.
It is an arithmetic number, because the mean of its divisors is an integer number (25020154141).
Almost surely, 250040308281 is an apocalyptic number.
It is an amenable number.
50040308281 is a deficient number, since it is larger than the sum of its proper divisors (1).
50040308281 is an equidigital number, since it uses as much as digits as its factorization.
50040308281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
The spelling of 50040308281 in words is "fifty billion, forty million, three hundred eight thousand, two hundred eighty-one".
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