Base | Representation |
---|---|
bin | 101110100111001101… |
… | …100110010010000011 |
3 | 11210012001220102201211 |
4 | 232213031212102003 |
5 | 1310000300000003 |
6 | 34554225110551 |
7 | 3421166660233 |
oct | 564715462203 |
9 | 153161812654 |
10 | 50050000003 |
11 | 1a253a13873 |
12 | 9849788457 |
13 | 4948228123 |
14 | 25cb227cc3 |
15 | 147de6e96d |
hex | ba7366483 |
50050000003 has 2 divisors, whose sum is σ = 50050000004. Its totient is φ = 50050000002.
The previous prime is 50049999991. The next prime is 50050000043. The reversal of 50050000003 is 30000005005.
50050000003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50050000003 is a prime.
It is not a weakly prime, because it can be changed into another prime (50050000043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25025000001 + 25025000002.
It is an arithmetic number, because the mean of its divisors is an integer number (25025000002).
Almost surely, 250050000003 is an apocalyptic number.
50050000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
50050000003 is an equidigital number, since it uses as much as digits as its factorization.
50050000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75, while the sum is 13.
Adding to 50050000003 its reverse (30000005005), we get a palindrome (80050005008).
The spelling of 50050000003 in words is "fifty billion, fifty million, three", and thus it is an aban number and an uban number.
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