Base | Representation |
---|---|
bin | 100100011010101000101… |
… | …0001101011111111110001 |
3 | 122201110210002102101111022 |
4 | 1020311101101223333301 |
5 | 1124000220111202433 |
6 | 14351133202225225 |
7 | 1024412402143106 |
oct | 110652121537761 |
9 | 18643702371438 |
10 | 5005000490993 |
11 | 165a67732a448 |
12 | 68a004655215 |
13 | 2a3c7b065489 |
14 | 134359934aad |
15 | 8a2d1723698 |
hex | 48d5146bff1 |
5005000490993 has 2 divisors, whose sum is σ = 5005000490994. Its totient is φ = 5005000490992.
The previous prime is 5005000490951. The next prime is 5005000491019. The reversal of 5005000490993 is 3990940005005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3894891708304 + 1110108782689 = 1973548^2 + 1053617^2 .
It is a cyclic number.
It is not a de Polignac number, because 5005000490993 - 240 = 3905488863217 is a prime.
It is not a weakly prime, because it can be changed into another prime (5005000490923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2502500245496 + 2502500245497.
It is an arithmetic number, because the mean of its divisors is an integer number (2502500245497).
Almost surely, 25005000490993 is an apocalyptic number.
It is an amenable number.
5005000490993 is a deficient number, since it is larger than the sum of its proper divisors (1).
5005000490993 is an equidigital number, since it uses as much as digits as its factorization.
5005000490993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 218700, while the sum is 44.
Adding to 5005000490993 its reverse (3990940005005), we get a palindrome (8995940495998).
The spelling of 5005000490993 in words is "five trillion, five billion, four hundred ninety thousand, nine hundred ninety-three".
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