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50050605555113 is a prime number
BaseRepresentation
bin10110110000101010100001…
…00100001001110110101001
320120012210100202102211012212
423120111100210021312221
523030012120010230423
6254240533014014505
713354015443510512
oct1330252044116651
9216183322384185
1050050605555113
1114a47385023709
125744186647435
1321c09a0a84c27
14c50668529a09
155bbde776d578
hex2d8550909da9

50050605555113 has 2 divisors, whose sum is σ = 50050605555114. Its totient is φ = 50050605555112.

The previous prime is 50050605554947. The next prime is 50050605555143. The reversal of 50050605555113 is 31155550605005.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44080729406224 + 5969876148889 = 6639332^2 + 2443333^2 .

It is a cyclic number.

It is not a de Polignac number, because 50050605555113 - 244 = 32458419510697 is a prime.

It is not a weakly prime, because it can be changed into another prime (50050605555143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25025302777556 + 25025302777557.

It is an arithmetic number, because the mean of its divisors is an integer number (25025302777557).

Almost surely, 250050605555113 is an apocalyptic number.

It is an amenable number.

50050605555113 is a deficient number, since it is larger than the sum of its proper divisors (1).

50050605555113 is an equidigital number, since it uses as much as digits as its factorization.

50050605555113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 281250, while the sum is 41.

The spelling of 50050605555113 in words is "fifty trillion, fifty billion, six hundred five million, five hundred fifty-five thousand, one hundred thirteen".