Base | Representation |
---|---|
bin | 10110110000110001000101… |
… | …10100010101011001001011 |
3 | 20120020010110120222012102211 |
4 | 23120120202310111121023 |
5 | 23030041331022341133 |
6 | 254242315023405551 |
7 | 13354202035424506 |
oct | 1330304264253113 |
9 | 216203416865384 |
10 | 50054133012043 |
11 | 14a489251a4276 |
12 | 57449aba538b7 |
13 | 21c1113815b54 |
14 | c508c0bd413d |
15 | 5bc0522a0bcd |
hex | 2d8622d1564b |
50054133012043 has 2 divisors, whose sum is σ = 50054133012044. Its totient is φ = 50054133012042.
The previous prime is 50054133012019. The next prime is 50054133012101. The reversal of 50054133012043 is 34021033145005.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50054133012043 - 213 = 50054133003851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50054133011996 and 50054133012014.
It is not a weakly prime, because it can be changed into another prime (50054133112043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25027066506021 + 25027066506022.
It is an arithmetic number, because the mean of its divisors is an integer number (25027066506022).
Almost surely, 250054133012043 is an apocalyptic number.
50054133012043 is a deficient number, since it is larger than the sum of its proper divisors (1).
50054133012043 is an equidigital number, since it uses as much as digits as its factorization.
50054133012043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 50054133012043 its reverse (34021033145005), we get a palindrome (84075166157048).
The spelling of 50054133012043 in words is "fifty trillion, fifty-four billion, one hundred thirty-three million, twelve thousand, forty-three".
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