Base | Representation |
---|---|
bin | 1110100100010110001… |
… | …10101101110111111001 |
3 | 1202212000012010121120101 |
4 | 13102023012231313321 |
5 | 31200111300000441 |
6 | 1021541031355401 |
7 | 51110044541263 |
oct | 7221306556771 |
9 | 1685005117511 |
10 | 500550000121 |
11 | 183311475756 |
12 | 81015222b61 |
13 | 3828108b332 |
14 | 1a3262b2b33 |
15 | d049076231 |
hex | 748b1addf9 |
500550000121 has 2 divisors, whose sum is σ = 500550000122. Its totient is φ = 500550000120.
The previous prime is 500550000103. The next prime is 500550000133. The reversal of 500550000121 is 121000055005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 481720671721 + 18829328400 = 694061^2 + 137220^2 .
It is a cyclic number.
It is not a de Polignac number, because 500550000121 - 25 = 500550000089 is a prime.
It is a super-2 number, since 2×5005500001212 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (500550000161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250275000060 + 250275000061.
It is an arithmetic number, because the mean of its divisors is an integer number (250275000061).
Almost surely, 2500550000121 is an apocalyptic number.
It is an amenable number.
500550000121 is a deficient number, since it is larger than the sum of its proper divisors (1).
500550000121 is an equidigital number, since it uses as much as digits as its factorization.
500550000121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 250, while the sum is 19.
Adding to 500550000121 its reverse (121000055005), we get a palindrome (621550055126).
The spelling of 500550000121 in words is "five hundred billion, five hundred fifty million, one hundred twenty-one", and thus it is an aban number.
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