Base | Representation |
---|---|
bin | 10110110000110010110000… |
… | …10010000101010101101111 |
3 | 20120020012210002211001210011 |
4 | 23120121120102011111233 |
5 | 23030100200140044210 |
6 | 254242544025154051 |
7 | 13354233206631610 |
oct | 1330313022052557 |
9 | 216205702731704 |
10 | 50055030003055 |
11 | 14a49245560960 |
12 | 574500032b927 |
13 | 21c12275c7a6c |
14 | c50967da9c07 |
15 | 5bc0a5dd5d8a |
hex | 2d865848556f |
50055030003055 has 32 divisors (see below), whose sum is σ = 74889590220288. Its totient is φ = 31202275248000.
The previous prime is 50055030003053. The next prime is 50055030003067. The reversal of 50055030003055 is 55030003055005.
It is not a de Polignac number, because 50055030003055 - 21 = 50055030003053 is a prime.
It is a super-3 number, since 3×500550300030553 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50055030003053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12333505 + ... + 15881605.
It is an arithmetic number, because the mean of its divisors is an integer number (2340299694384).
Almost surely, 250055030003055 is an apocalyptic number.
50055030003055 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
50055030003055 is a deficient number, since it is larger than the sum of its proper divisors (24834560217233).
50055030003055 is a wasteful number, since it uses less digits than its factorization.
50055030003055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3584767.
The product of its (nonzero) digits is 28125, while the sum is 31.
The spelling of 50055030003055 in words is "fifty trillion, fifty-five billion, thirty million, three thousand, fifty-five".
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