Search a number
-
+
500555500433 is a prime number
BaseRepresentation
bin1110100100010110110…
…11101100101110010001
31202212000120111001120122
413102023123230232101
531200114202003213
61021541345320025
751110142360212
oct7221333545621
91685016431518
10500555500433
1118331459216a
1281017036015
1338282265a61
141a326d05409
15d0497b0d08
hex748b6ecb91

500555500433 has 2 divisors, whose sum is σ = 500555500434. Its totient is φ = 500555500432.

The previous prime is 500555500427. The next prime is 500555500469. The reversal of 500555500433 is 334005555005.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 458893791889 + 41661708544 = 677417^2 + 204112^2 .

It is a cyclic number.

It is not a de Polignac number, because 500555500433 - 218 = 500555238289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 500555500393 and 500555500402.

It is not a weakly prime, because it can be changed into another prime (500555500633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250277750216 + 250277750217.

It is an arithmetic number, because the mean of its divisors is an integer number (250277750217).

Almost surely, 2500555500433 is an apocalyptic number.

It is an amenable number.

500555500433 is a deficient number, since it is larger than the sum of its proper divisors (1).

500555500433 is an equidigital number, since it uses as much as digits as its factorization.

500555500433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112500, while the sum is 35.

The spelling of 500555500433 in words is "five hundred billion, five hundred fifty-five million, five hundred thousand, four hundred thirty-three".