Base | Representation |
---|---|
bin | 10110110001110000001111… |
… | …00111100010011011111011 |
3 | 20120100100222101012022201112 |
4 | 23120320013213202123323 |
5 | 23031120244310124011 |
6 | 254310043135110535 |
7 | 13356512143522565 |
oct | 1330700747423373 |
9 | 216310871168645 |
10 | 50088036411131 |
11 | 14a61242841864 |
12 | 574b49207244b |
13 | 21c43877a9044 |
14 | c523b9808335 |
15 | 5bcd8891c58b |
hex | 2d8e079e26fb |
50088036411131 has 2 divisors, whose sum is σ = 50088036411132. Its totient is φ = 50088036411130.
The previous prime is 50088036411109. The next prime is 50088036411163. The reversal of 50088036411131 is 13111463088005.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50088036411131 - 230 = 50086962669307 is a prime.
It is a super-2 number, since 2×500880364111312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50088036410131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25044018205565 + 25044018205566.
It is an arithmetic number, because the mean of its divisors is an integer number (25044018205566).
Almost surely, 250088036411131 is an apocalyptic number.
50088036411131 is a deficient number, since it is larger than the sum of its proper divisors (1).
50088036411131 is an equidigital number, since it uses as much as digits as its factorization.
50088036411131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 41.
Adding to 50088036411131 its reverse (13111463088005), we get a palindrome (63199499499136).
The spelling of 50088036411131 in words is "fifty trillion, eighty-eight billion, thirty-six million, four hundred eleven thousand, one hundred thirty-one".
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