Base | Representation |
---|---|
bin | 10110110010000110100010… |
… | …10011001100010110010011 |
3 | 20120101111212211122011112102 |
4 | 23121003101103030112103 |
5 | 23031314310030310003 |
6 | 254315343222551015 |
7 | 13360414644450242 |
oct | 1331032123142623 |
9 | 216344784564472 |
10 | 50100010010003 |
11 | 14a66327600918 |
12 | 5751873b9846b |
13 | 21c55453289a5 |
14 | c52bd3b12959 |
15 | 5bd339bc5588 |
hex | 2d90d14cc593 |
50100010010003 has 2 divisors, whose sum is σ = 50100010010004. Its totient is φ = 50100010010002.
The previous prime is 50100010009993. The next prime is 50100010010027. The reversal of 50100010010003 is 30001001000105.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50100010010003 - 220 = 50100008961427 is a prime.
It is a super-2 number, since 2×501000100100032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50100010010203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25050005005001 + 25050005005002.
It is an arithmetic number, because the mean of its divisors is an integer number (25050005005002).
Almost surely, 250100010010003 is an apocalyptic number.
50100010010003 is a deficient number, since it is larger than the sum of its proper divisors (1).
50100010010003 is an equidigital number, since it uses as much as digits as its factorization.
50100010010003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15, while the sum is 11.
Adding to 50100010010003 its reverse (30001001000105), we get a palindrome (80101011010108).
The spelling of 50100010010003 in words is "fifty trillion, one hundred billion, ten million, ten thousand, three".
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