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501001100113 is a prime number
BaseRepresentation
bin1110100101001011111…
…11100001101101010001
31202220011121221212102111
413102211333201231101
531202022240200423
61022053504145321
751124163041513
oct7224577415521
91686147855374
10501001100113
11183523072868
1281120308241
13383236818c7
141a36a179bb3
15d07398060d
hex74a5fe1b51

501001100113 has 2 divisors, whose sum is σ = 501001100114. Its totient is φ = 501001100112.

The previous prime is 501001100077. The next prime is 501001100179. The reversal of 501001100113 is 311001100105.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 378461196864 + 122539903249 = 615192^2 + 350057^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-501001100113 is a prime.

It is a super-2 number, since 2×5010011001132 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 501001100093 and 501001100102.

It is not a weakly prime, because it can be changed into another prime (501001106113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250500550056 + 250500550057.

It is an arithmetic number, because the mean of its divisors is an integer number (250500550057).

Almost surely, 2501001100113 is an apocalyptic number.

It is an amenable number.

501001100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

501001100113 is an equidigital number, since it uses as much as digits as its factorization.

501001100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 501001100113 its reverse (311001100105), we get a palindrome (812002200218).

The spelling of 501001100113 in words is "five hundred one billion, one million, one hundred thousand, one hundred thirteen".