Base | Representation |
---|---|
bin | 101110101010001101… |
… | …101011110101100001 |
3 | 11210022120122200222112 |
4 | 232222031223311201 |
5 | 1310101142320101 |
6 | 35003224245105 |
7 | 3422350662116 |
oct | 565215536541 |
9 | 153276580875 |
10 | 50100354401 |
11 | 1a27a386879 |
12 | 9862610795 |
13 | 49557a8926 |
14 | 25d3bb490d |
15 | 14835b96bb |
hex | baa36bd61 |
50100354401 has 2 divisors, whose sum is σ = 50100354402. Its totient is φ = 50100354400.
The previous prime is 50100354323. The next prime is 50100354419. The reversal of 50100354401 is 10445300105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27763557376 + 22336797025 = 166624^2 + 149455^2 .
It is a cyclic number.
It is not a de Polignac number, because 50100354401 - 210 = 50100353377 is a prime.
It is a super-2 number, since 2×501003544012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50100354431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25050177200 + 25050177201.
It is an arithmetic number, because the mean of its divisors is an integer number (25050177201).
Almost surely, 250100354401 is an apocalyptic number.
It is an amenable number.
50100354401 is a deficient number, since it is larger than the sum of its proper divisors (1).
50100354401 is an equidigital number, since it uses as much as digits as its factorization.
50100354401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 50100354401 its reverse (10445300105), we get a palindrome (60545654506).
The spelling of 50100354401 in words is "fifty billion, one hundred million, three hundred fifty-four thousand, four hundred one".
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