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5010062157433 is a prime number
BaseRepresentation
bin100100011100111111011…
…1110011010011001111001
3122201221211211211200111201
41020321332332122121321
51124041101403014213
614353331335254201
71024652003455114
oct110717676323171
918657754750451
105010062157433
111661834526353
1268ab9781a361
132a45a6905688
141346b9c8957b
158a4cacab6dd
hex48e7ef9a679

5010062157433 has 2 divisors, whose sum is σ = 5010062157434. Its totient is φ = 5010062157432.

The previous prime is 5010062157349. The next prime is 5010062157461. The reversal of 5010062157433 is 3347512600105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3066971130729 + 1943091026704 = 1751277^2 + 1393948^2 .

It is a cyclic number.

It is not a de Polignac number, because 5010062157433 - 29 = 5010062156921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5010062157392 and 5010062157401.

It is not a weakly prime, because it can be changed into another prime (5010062157473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505031078716 + 2505031078717.

It is an arithmetic number, because the mean of its divisors is an integer number (2505031078717).

Almost surely, 25010062157433 is an apocalyptic number.

It is an amenable number.

5010062157433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5010062157433 is an equidigital number, since it uses as much as digits as its factorization.

5010062157433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75600, while the sum is 37.

Adding to 5010062157433 its reverse (3347512600105), we get a palindrome (8357574757538).

The spelling of 5010062157433 in words is "five trillion, ten billion, sixty-two million, one hundred fifty-seven thousand, four hundred thirty-three".