Base | Representation |
---|---|
bin | 101110101010010000… |
… | …100101010101100011 |
3 | 11210022122002022020122 |
4 | 232222100211111203 |
5 | 1310101341123321 |
6 | 35003252430455 |
7 | 3422360305241 |
oct | 565220452543 |
9 | 153278068218 |
10 | 50101114211 |
11 | 1a27a855715 |
12 | 986291842b |
13 | 49559b3715 |
14 | 25d3d31791 |
15 | 14836b98ab |
hex | baa425563 |
50101114211 has 2 divisors, whose sum is σ = 50101114212. Its totient is φ = 50101114210.
The previous prime is 50101114187. The next prime is 50101114223. The reversal of 50101114211 is 11241110105.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50101114211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 50101114211.
It is not a weakly prime, because it can be changed into another prime (50101114711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25050557105 + 25050557106.
It is an arithmetic number, because the mean of its divisors is an integer number (25050557106).
Almost surely, 250101114211 is an apocalyptic number.
50101114211 is a deficient number, since it is larger than the sum of its proper divisors (1).
50101114211 is an equidigital number, since it uses as much as digits as its factorization.
50101114211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 50101114211 its reverse (11241110105), we get a palindrome (61342224316).
The spelling of 50101114211 in words is "fifty billion, one hundred one million, one hundred fourteen thousand, two hundred eleven".
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