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5010412114303 = 35291528992863
BaseRepresentation
bin100100011101001001111…
…0101011001000101111111
3122201222202020100100002021
41020322103311121011333
51124042311000124203
614353430200141011
71024663453162411
oct110722365310577
918658666310067
105010412114303
1116619a4021102
1268b074a67767
132a463127504b
141347105449b1
158a4eb8875bd
hex48e93d5917f

5010412114303 has 8 divisors (see below), whose sum is σ = 5012213676800. Its totient is φ = 5008610775168.

The previous prime is 5010412114271. The next prime is 5010412114343. The reversal of 5010412114303 is 3034112140105.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5010412114303 - 25 = 5010412114271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5010412114343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53908450 + ... + 54001312.

It is an arithmetic number, because the mean of its divisors is an integer number (626526709600).

Almost surely, 25010412114303 is an apocalyptic number.

5010412114303 is a deficient number, since it is larger than the sum of its proper divisors (1801562497).

5010412114303 is a wasteful number, since it uses less digits than its factorization.

5010412114303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111681.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 5010412114303 its reverse (3034112140105), we get a palindrome (8044524254408).

The spelling of 5010412114303 in words is "five trillion, ten billion, four hundred twelve million, one hundred fourteen thousand, three hundred three".

Divisors: 1 3529 15289 92863 53954881 327713527 1419782407 5010412114303