Base | Representation |
---|---|
bin | 101110101010100011… |
… | …010000110101111011 |
3 | 11210022222022002101022 |
4 | 232222203100311323 |
5 | 1310104114323003 |
6 | 35003545413055 |
7 | 3422450031506 |
oct | 565243206573 |
9 | 153288262338 |
10 | 50106011003 |
11 | 1a28259a754 |
12 | 986449a18b |
13 | 4956a09529 |
14 | 25d484813d |
15 | 1483d35738 |
hex | baa8d0d7b |
50106011003 has 2 divisors, whose sum is σ = 50106011004. Its totient is φ = 50106011002.
The previous prime is 50106010951. The next prime is 50106011093. The reversal of 50106011003 is 30011060105.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50106011003 - 224 = 50089233787 is a prime.
It is a super-2 number, since 2×501060110032 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50106011093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25053005501 + 25053005502.
It is an arithmetic number, because the mean of its divisors is an integer number (25053005502).
Almost surely, 250106011003 is an apocalyptic number.
50106011003 is a deficient number, since it is larger than the sum of its proper divisors (1).
50106011003 is an equidigital number, since it uses as much as digits as its factorization.
50106011003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 50106011003 its reverse (30011060105), we get a palindrome (80117071108).
The spelling of 50106011003 in words is "fifty billion, one hundred six million, eleven thousand, three".
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