Base | Representation |
---|---|
bin | 10110110010011010001011… |
… | …10101100011110100100011 |
3 | 20120102112002202002210020011 |
4 | 23121031011311203310203 |
5 | 23032002404102020231 |
6 | 254324245441025351 |
7 | 13361240161360105 |
oct | 1331150565436443 |
9 | 216375082083204 |
10 | 50110555110691 |
11 | 14a6a848a87069 |
12 | 5753917625257 |
13 | 21c6535c2c63a |
14 | c5351440b575 |
15 | 5bd7558599b1 |
hex | 2d9345d63d23 |
50110555110691 has 2 divisors, whose sum is σ = 50110555110692. Its totient is φ = 50110555110690.
The previous prime is 50110555110667. The next prime is 50110555110767. The reversal of 50110555110691 is 19601155501105.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50110555110691 - 223 = 50110546722083 is a prime.
It is a super-2 number, since 2×501105551106912 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50110555117691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25055277555345 + 25055277555346.
It is an arithmetic number, because the mean of its divisors is an integer number (25055277555346).
Almost surely, 250110555110691 is an apocalyptic number.
50110555110691 is a deficient number, since it is larger than the sum of its proper divisors (1).
50110555110691 is an equidigital number, since it uses as much as digits as its factorization.
50110555110691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33750, while the sum is 40.
The spelling of 50110555110691 in words is "fifty trillion, one hundred ten billion, five hundred fifty-five million, one hundred ten thousand, six hundred ninety-one".
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