Base | Representation |
---|---|
bin | 10110110010011101101001… |
… | …00101101010100110011100 |
3 | 20120102200220020110021100011 |
4 | 23121032310211222212130 |
5 | 23032020210240341012 |
6 | 254325154054413004 |
7 | 13361334213115162 |
oct | 1331166445524634 |
9 | 216380806407304 |
10 | 50112413215132 |
11 | 14a70611917474 |
12 | 5754155961164 |
13 | 21c6770b84918 |
14 | c5364d0cb232 |
15 | 5bd813a3e1a7 |
hex | 2d93b496a99c |
50112413215132 has 6 divisors (see below), whose sum is σ = 87696723126488. Its totient is φ = 25056206607564.
The previous prime is 50112413215097. The next prime is 50112413215153. The reversal of 50112413215132 is 23151231421105.
It is a super-2 number, since 2×501124132151322 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50112413215094 and 50112413215103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6264051651888 + ... + 6264051651895.
Almost surely, 250112413215132 is an apocalyptic number.
It is an amenable number.
50112413215132 is a deficient number, since it is larger than the sum of its proper divisors (37584309911356).
50112413215132 is a wasteful number, since it uses less digits than its factorization.
50112413215132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12528103303787 (or 12528103303785 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 50112413215132 its reverse (23151231421105), we get a palindrome (73263644636237).
The spelling of 50112413215132 in words is "fifty trillion, one hundred twelve billion, four hundred thirteen million, two hundred fifteen thousand, one hundred thirty-two".
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