Base | Representation |
---|---|
bin | 10110110010011111000000… |
… | …01001111000111000100001 |
3 | 20120102202210011210122120010 |
4 | 23121033200021320320201 |
5 | 23032023204344143410 |
6 | 254325354404435133 |
7 | 13361361266601426 |
oct | 1331174011707041 |
9 | 216382704718503 |
10 | 50113144131105 |
11 | 14a70957462460 |
12 | 575431a6a8aa9 |
13 | 21c6859429b93 |
14 | c536bc1d1d4d |
15 | 5bd857cbbc20 |
hex | 2d93e0278e21 |
50113144131105 has 64 divisors (see below), whose sum is σ = 87649433337600. Its totient is φ = 24247524126720.
The previous prime is 50113144131077. The next prime is 50113144131119.
50113144131105 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 50113144131105 - 222 = 50113139936801 is a prime.
It is a super-2 number, since 2×501131441311052 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 330117661 + ... + 330269429.
It is an arithmetic number, because the mean of its divisors is an integer number (1369522395900).
Almost surely, 250113144131105 is an apocalyptic number.
50113144131105 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
50113144131105 is a deficient number, since it is larger than the sum of its proper divisors (37536289206495).
50113144131105 is a wasteful number, since it uses less digits than its factorization.
50113144131105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 155874.
The product of its (nonzero) digits is 3600, while the sum is 30.
It can be divided in two parts, 5011314 and 4131105, that added together give a palindrome (9142419).
The spelling of 50113144131105 in words is "fifty trillion, one hundred thirteen billion, one hundred forty-four million, one hundred thirty-one thousand, one hundred five".
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