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5011324001 is a prime number
BaseRepresentation
bin1001010101011001…
…01011110001100001
3110221020200122011122
410222230223301201
540230344332001
62145134022025
7235120360025
oct45254536141
913836618148
105011324001
112141841992
12b7a347915
1361b2c4c98
143577ac385
151e4e41b1b
hex12ab2bc61

5011324001 has 2 divisors, whose sum is σ = 5011324002. Its totient is φ = 5011324000.

The previous prime is 5011323907. The next prime is 5011324007. The reversal of 5011324001 is 1004231105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4518528400 + 492795601 = 67220^2 + 22199^2 .

It is a cyclic number.

It is not a de Polignac number, because 5011324001 - 218 = 5011061857 is a prime.

It is a super-2 number, since 2×50113240012 = 50226736485997296002, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5011324007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505662000 + 2505662001.

It is an arithmetic number, because the mean of its divisors is an integer number (2505662001).

Almost surely, 25011324001 is an apocalyptic number.

It is an amenable number.

5011324001 is a deficient number, since it is larger than the sum of its proper divisors (1).

5011324001 is an equidigital number, since it uses as much as digits as its factorization.

5011324001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 5011324001 is about 70790.7056116832. The cubic root of 5011324001 is about 1711.2658912993.

Adding to 5011324001 its reverse (1004231105), we get a palindrome (6015555106).

The spelling of 5011324001 in words is "five billion, eleven million, three hundred twenty-four thousand, one".