50113431131 has 2 divisors, whose sum is σ = 50113431132. Its totient is φ = 50113431130.

The previous prime is 50113431101. The next prime is 50113431187. The reversal of 50113431131 is 13113431105.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-50113431131 is a prime.

It is a super-2 number, since 2×50113431131² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50113431097 and 50113431106.

It is not a weakly prime, because it can be changed into another prime (50113431101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25056715565 + 25056715566.

It is an arithmetic number, because the mean of its divisors is an integer number (25056715566).

Almost surely, 2^50113431131 is an apocalyptic number.

50113431131 is a deficient number, since it is larger than the sum of its proper divisors (1).

50113431131 is an equidigital number, since it uses as much as digits as its factorization.

50113431131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 50113431131 its reverse (13113431105), we get a palindrome (63226862236).

The spelling of 50113431131 in words is "fifty billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred thirty-one".