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501214245343153 is a prime number
BaseRepresentation
bin111000111110110100000100…
…1000011001100111110110001
32102201122121120112102011111221
41301331220021003030332301
51011143343233301440103
64533554351241305041
7210400351146164416
oct16175501103147661
92381577515364457
10501214245343153
1113577a849960031
124826a818795181
13186893ba35c414
148baac8288410d
153ce2aed0311bd
hex1c7da090ccfb1

501214245343153 has 2 divisors, whose sum is σ = 501214245343154. Its totient is φ = 501214245343152.

The previous prime is 501214245343139. The next prime is 501214245343157. The reversal of 501214245343153 is 351343542412105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 373419178939249 + 127795066403904 = 19324057^2 + 11304648^2 .

It is a cyclic number.

It is not a de Polignac number, because 501214245343153 - 221 = 501214243246001 is a prime.

It is not a weakly prime, because it can be changed into another prime (501214245343157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250607122671576 + 250607122671577.

It is an arithmetic number, because the mean of its divisors is an integer number (250607122671577).

Almost surely, 2501214245343153 is an apocalyptic number.

It is an amenable number.

501214245343153 is a deficient number, since it is larger than the sum of its proper divisors (1).

501214245343153 is an equidigital number, since it uses as much as digits as its factorization.

501214245343153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 501214245343153 its reverse (351343542412105), we get a palindrome (852557787755258).

The spelling of 501214245343153 in words is "five hundred one trillion, two hundred fourteen billion, two hundred forty-five million, three hundred forty-three thousand, one hundred fifty-three".