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50128087853 = 291717184809
BaseRepresentation
bin101110101011110111…
…011110101100101101
311210101111211201010102
4232223313132230231
51310130242302403
635010054520445
73423135500504
oct565367365455
9153344751112
1050128087853
111a293aa9388
12986b966125
13495b46905c
1425d775383b
151485c46b88
hexbabddeb2d

50128087853 has 4 divisors (see below), whose sum is σ = 50145275580. Its totient is φ = 50110900128.

The previous prime is 50128087777. The next prime is 50128087859. The reversal of 50128087853 is 35878082105.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 44431159369 + 5696928484 = 210787^2 + 75478^2 .

It is a cyclic number.

It is not a de Polignac number, because 50128087853 - 228 = 49859652397 is a prime.

It is a super-2 number, since 2×501280878532 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50128087798 and 50128087807.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50128087859) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8589488 + ... + 8595321.

It is an arithmetic number, because the mean of its divisors is an integer number (12536318895).

Almost surely, 250128087853 is an apocalyptic number.

It is an amenable number.

50128087853 is a deficient number, since it is larger than the sum of its proper divisors (17187727).

50128087853 is a wasteful number, since it uses less digits than its factorization.

50128087853 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17187726.

The product of its (nonzero) digits is 537600, while the sum is 47.

The spelling of 50128087853 in words is "fifty billion, one hundred twenty-eight million, eighty-seven thousand, eight hundred fifty-three".

Divisors: 1 2917 17184809 50128087853