Base | Representation |
---|---|
bin | 1110100101110001000… |
… | …10000100011100000001 |
3 | 1202220222022020121000011 |
4 | 13102320202010130001 |
5 | 31203141402121103 |
6 | 1022144415024521 |
7 | 51134660632411 |
oct | 7227042043401 |
9 | 1686868217004 |
10 | 501312145153 |
11 | 183672700586 |
12 | 811a850b141 |
13 | 38372c48b21 |
14 | 1a3995c6641 |
15 | d090e21d6d |
hex | 74b8884701 |
501312145153 has 2 divisors, whose sum is σ = 501312145154. Its totient is φ = 501312145152.
The previous prime is 501312145133. The next prime is 501312145157. The reversal of 501312145153 is 351541213105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 314919625329 + 186392519824 = 561177^2 + 431732^2 .
It is a cyclic number.
It is not a de Polignac number, because 501312145153 - 217 = 501312014081 is a prime.
It is not a weakly prime, because it can be changed into another prime (501312145157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250656072576 + 250656072577.
It is an arithmetic number, because the mean of its divisors is an integer number (250656072577).
Almost surely, 2501312145153 is an apocalyptic number.
It is an amenable number.
501312145153 is a deficient number, since it is larger than the sum of its proper divisors (1).
501312145153 is an equidigital number, since it uses as much as digits as its factorization.
501312145153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 501312145153 its reverse (351541213105), we get a palindrome (852853358258).
The spelling of 501312145153 in words is "five hundred one billion, three hundred twelve million, one hundred forty-five thousand, one hundred fifty-three".
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