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50143301433 = 3231365927011
BaseRepresentation
bin101110101100110001…
…100000111100111001
311210102120110122020100
4232230301200330321
51310143141121213
635011400550013
73423412013121
oct565461407471
9153376418210
1050143301433
111a2a164a595
129874a82309
134961664984
1425d9793c81
15148724e773
hexbacc60f39

50143301433 has 24 divisors (see below), whose sum is σ = 72773569440. Its totient is φ = 33270269760.

The previous prime is 50143301419. The next prime is 50143301441. The reversal of 50143301433 is 33410334105.

It is not a de Polignac number, because 50143301433 - 210 = 50143300409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50143301397 and 50143301406.

It is not an unprimeable number, because it can be changed into a prime (50143303433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1842898 + ... + 1869908.

It is an arithmetic number, because the mean of its divisors is an integer number (3032232060).

Almost surely, 250143301433 is an apocalyptic number.

It is an amenable number.

50143301433 is a deficient number, since it is larger than the sum of its proper divisors (22630268007).

50143301433 is a wasteful number, since it uses less digits than its factorization.

50143301433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27989 (or 27986 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 27.

Adding to 50143301433 its reverse (33410334105), we get a palindrome (83553635538).

The spelling of 50143301433 in words is "fifty billion, one hundred forty-three million, three hundred one thousand, four hundred thirty-three".

Divisors: 1 3 9 313 659 939 1977 2817 5931 27011 81033 206267 243099 618801 1856403 8454443 17800249 25363329 53400747 76089987 160202241 5571477937 16714433811 50143301433