Base | Representation |
---|---|
bin | 101110101100110001… |
… | …100000111100111001 |
3 | 11210102120110122020100 |
4 | 232230301200330321 |
5 | 1310143141121213 |
6 | 35011400550013 |
7 | 3423412013121 |
oct | 565461407471 |
9 | 153376418210 |
10 | 50143301433 |
11 | 1a2a164a595 |
12 | 9874a82309 |
13 | 4961664984 |
14 | 25d9793c81 |
15 | 148724e773 |
hex | bacc60f39 |
50143301433 has 24 divisors (see below), whose sum is σ = 72773569440. Its totient is φ = 33270269760.
The previous prime is 50143301419. The next prime is 50143301441. The reversal of 50143301433 is 33410334105.
It is not a de Polignac number, because 50143301433 - 210 = 50143300409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50143301397 and 50143301406.
It is not an unprimeable number, because it can be changed into a prime (50143303433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1842898 + ... + 1869908.
It is an arithmetic number, because the mean of its divisors is an integer number (3032232060).
Almost surely, 250143301433 is an apocalyptic number.
It is an amenable number.
50143301433 is a deficient number, since it is larger than the sum of its proper divisors (22630268007).
50143301433 is a wasteful number, since it uses less digits than its factorization.
50143301433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27989 (or 27986 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 27.
Adding to 50143301433 its reverse (33410334105), we get a palindrome (83553635538).
The spelling of 50143301433 in words is "fifty billion, one hundred forty-three million, three hundred one thousand, four hundred thirty-three".
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