Base | Representation |
---|---|
bin | 10110110011100011101101… |
… | …11011110111000010101011 |
3 | 20120120022000001202101001201 |
4 | 23121301312323313002223 |
5 | 23033124232042122111 |
6 | 254354335105025031 |
7 | 13364135403522214 |
oct | 1331616673670253 |
9 | 216508001671051 |
10 | 50150033551531 |
11 | 14a85567592a81 |
12 | 575b4b4925177 |
13 | 21ca187c1bac4 |
14 | c553bb61040b |
15 | 5be7b666a6c1 |
hex | 2d9c76ef70ab |
50150033551531 has 2 divisors, whose sum is σ = 50150033551532. Its totient is φ = 50150033551530.
The previous prime is 50150033551493. The next prime is 50150033551537. The reversal of 50150033551531 is 13515533005105.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50150033551531 is a prime.
It is a super-2 number, since 2×501500335515312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50150033551537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25075016775765 + 25075016775766.
It is an arithmetic number, because the mean of its divisors is an integer number (25075016775766).
Almost surely, 250150033551531 is an apocalyptic number.
50150033551531 is a deficient number, since it is larger than the sum of its proper divisors (1).
50150033551531 is an equidigital number, since it uses as much as digits as its factorization.
50150033551531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84375, while the sum is 37.
Adding to 50150033551531 its reverse (13515533005105), we get a palindrome (63665566556636).
The spelling of 50150033551531 in words is "fifty trillion, one hundred fifty billion, thirty-three million, five hundred fifty-one thousand, five hundred thirty-one".
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