Base | Representation |
---|---|
bin | 101110101101010111… |
… | …010100000100000001 |
3 | 11210110021010001101111 |
4 | 232231113110010001 |
5 | 1310203210210423 |
6 | 35012353203321 |
7 | 3423562152316 |
oct | 565527240401 |
9 | 153407101344 |
10 | 50153210113 |
11 | 1a2a71a8086 |
12 | 9878260541 |
13 | 4963723ab6 |
14 | 25dac12d0d |
15 | 148805a60d |
hex | bad5d4101 |
50153210113 has 2 divisors, whose sum is σ = 50153210114. Its totient is φ = 50153210112.
The previous prime is 50153210101. The next prime is 50153210167. The reversal of 50153210113 is 31101235105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40861792449 + 9291417664 = 202143^2 + 96392^2 .
It is a cyclic number.
It is not a de Polignac number, because 50153210113 - 221 = 50151112961 is a prime.
It is a super-3 number, since 3×501532101133 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (50153210413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25076605056 + 25076605057.
It is an arithmetic number, because the mean of its divisors is an integer number (25076605057).
Almost surely, 250153210113 is an apocalyptic number.
It is an amenable number.
50153210113 is a deficient number, since it is larger than the sum of its proper divisors (1).
50153210113 is an equidigital number, since it uses as much as digits as its factorization.
50153210113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 50153210113 its reverse (31101235105), we get a palindrome (81254445218).
The spelling of 50153210113 in words is "fifty billion, one hundred fifty-three million, two hundred ten thousand, one hundred thirteen".
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