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50153210113 is a prime number
BaseRepresentation
bin101110101101010111…
…010100000100000001
311210110021010001101111
4232231113110010001
51310203210210423
635012353203321
73423562152316
oct565527240401
9153407101344
1050153210113
111a2a71a8086
129878260541
134963723ab6
1425dac12d0d
15148805a60d
hexbad5d4101

50153210113 has 2 divisors, whose sum is σ = 50153210114. Its totient is φ = 50153210112.

The previous prime is 50153210101. The next prime is 50153210167. The reversal of 50153210113 is 31101235105.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40861792449 + 9291417664 = 202143^2 + 96392^2 .

It is a cyclic number.

It is not a de Polignac number, because 50153210113 - 221 = 50151112961 is a prime.

It is a super-3 number, since 3×501532101133 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (50153210413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25076605056 + 25076605057.

It is an arithmetic number, because the mean of its divisors is an integer number (25076605057).

Almost surely, 250153210113 is an apocalyptic number.

It is an amenable number.

50153210113 is a deficient number, since it is larger than the sum of its proper divisors (1).

50153210113 is an equidigital number, since it uses as much as digits as its factorization.

50153210113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 50153210113 its reverse (31101235105), we get a palindrome (81254445218).

The spelling of 50153210113 in words is "fifty billion, one hundred fifty-three million, two hundred ten thousand, one hundred thirteen".