Base | Representation |
---|---|
bin | 100100100001110000101… |
… | …1101010010100010000011 |
3 | 122202221021122100011001111 |
4 | 1021003201131102202003 |
5 | 1124223040403302121 |
6 | 14402143533144151 |
7 | 1025463551626564 |
oct | 111034135224203 |
9 | 18687248304044 |
10 | 5020304353411 |
11 | 166610aa23826 |
12 | 690b7592b057 |
13 | 2a5549832379 |
14 | 134dac25616b |
15 | 8a8ca05b2e1 |
hex | 490e1752883 |
5020304353411 has 2 divisors, whose sum is σ = 5020304353412. Its totient is φ = 5020304353410.
The previous prime is 5020304353403. The next prime is 5020304353417. The reversal of 5020304353411 is 1143534030205.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5020304353411 - 23 = 5020304353403 is a prime.
It is not a weakly prime, because it can be changed into another prime (5020304353417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2510152176705 + 2510152176706.
It is an arithmetic number, because the mean of its divisors is an integer number (2510152176706).
Almost surely, 25020304353411 is an apocalyptic number.
5020304353411 is a deficient number, since it is larger than the sum of its proper divisors (1).
5020304353411 is an equidigital number, since it uses as much as digits as its factorization.
5020304353411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5020304353411 its reverse (1143534030205), we get a palindrome (6163838383616).
The spelling of 5020304353411 in words is "five trillion, twenty billion, three hundred four million, three hundred fifty-three thousand, four hundred eleven".
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