Base | Representation |
---|---|
bin | 100100100001110001110… |
… | …0101011110110101001011 |
3 | 122202221101010111222221022 |
4 | 1021003203211132311023 |
5 | 1124223124023232441 |
6 | 14402151250303055 |
7 | 1025464464244124 |
oct | 111034345366513 |
9 | 18687333458838 |
10 | 5020340055371 |
11 | 1666129099183 |
12 | 690b85887a8b |
13 | 2a55540527a4 |
14 | 134db2cab04b |
15 | 8a8cd25e84b |
hex | 490e395ed4b |
5020340055371 has 2 divisors, whose sum is σ = 5020340055372. Its totient is φ = 5020340055370.
The previous prime is 5020340055331. The next prime is 5020340055377. The reversal of 5020340055371 is 1735500430205.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5020340055371 is a prime.
It is not a weakly prime, because it can be changed into another prime (5020340055377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2510170027685 + 2510170027686.
It is an arithmetic number, because the mean of its divisors is an integer number (2510170027686).
Almost surely, 25020340055371 is an apocalyptic number.
5020340055371 is a deficient number, since it is larger than the sum of its proper divisors (1).
5020340055371 is an equidigital number, since it uses as much as digits as its factorization.
5020340055371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 35.
Adding to 5020340055371 its reverse (1735500430205), we get a palindrome (6755840485576).
The spelling of 5020340055371 in words is "five trillion, twenty billion, three hundred forty million, fifty-five thousand, three hundred seventy-one".
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