Base | Representation |
---|---|
bin | 1110100111010010100… |
… | …01111100000001111001 |
3 | 1210000002022011220221011 |
4 | 13103221101330001321 |
5 | 31211330234444433 |
6 | 1022401512313521 |
7 | 51164151402016 |
oct | 7235121740171 |
9 | 1700068156834 |
10 | 502129999993 |
11 | 183a52326a76 |
12 | 813963a28a1 |
13 | 384735108bb |
14 | 1a43607c70d |
15 | d0dcb243cd |
hex | 74e947c079 |
502129999993 has 2 divisors, whose sum is σ = 502129999994. Its totient is φ = 502129999992.
The previous prime is 502129999939. The next prime is 502130000027. The reversal of 502129999993 is 399999921205.
Together with previous prime (502129999939) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 485485645824 + 16644354169 = 696768^2 + 129013^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-502129999993 is a prime.
It is not a weakly prime, because it can be changed into another prime (502129999493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251064999996 + 251064999997.
It is an arithmetic number, because the mean of its divisors is an integer number (251064999997).
Almost surely, 2502129999993 is an apocalyptic number.
It is an amenable number.
502129999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
502129999993 is an equidigital number, since it uses as much as digits as its factorization.
502129999993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31886460, while the sum is 67.
The spelling of 502129999993 in words is "five hundred two billion, one hundred twenty-nine million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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