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502129999993 is a prime number
BaseRepresentation
bin1110100111010010100…
…01111100000001111001
31210000002022011220221011
413103221101330001321
531211330234444433
61022401512313521
751164151402016
oct7235121740171
91700068156834
10502129999993
11183a52326a76
12813963a28a1
13384735108bb
141a43607c70d
15d0dcb243cd
hex74e947c079

502129999993 has 2 divisors, whose sum is σ = 502129999994. Its totient is φ = 502129999992.

The previous prime is 502129999939. The next prime is 502130000027. The reversal of 502129999993 is 399999921205.

Together with previous prime (502129999939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 485485645824 + 16644354169 = 696768^2 + 129013^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-502129999993 is a prime.

It is not a weakly prime, because it can be changed into another prime (502129999493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251064999996 + 251064999997.

It is an arithmetic number, because the mean of its divisors is an integer number (251064999997).

Almost surely, 2502129999993 is an apocalyptic number.

It is an amenable number.

502129999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

502129999993 is an equidigital number, since it uses as much as digits as its factorization.

502129999993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31886460, while the sum is 67.

The spelling of 502129999993 in words is "five hundred two billion, one hundred twenty-nine million, nine hundred ninety-nine thousand, nine hundred ninety-three".