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5022525345433 is a prime number
BaseRepresentation
bin100100100010110010111…
…0101101100111010011001
3122210011000102112020100021
41021011211311230322121
51124242112442023213
614403152152510441
71025602601016151
oct111054565547231
918704012466307
105022525345433
11166704a690a22
126914956ab421
132a5811a0382b
1413513d1d9761
158a9aa022d8d
hex49165d6ce99

5022525345433 has 2 divisors, whose sum is σ = 5022525345434. Its totient is φ = 5022525345432.

The previous prime is 5022525345413. The next prime is 5022525345457. The reversal of 5022525345433 is 3345435252205.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5021780710489 + 744634944 = 2240933^2 + 27288^2 .

It is a cyclic number.

It is not a de Polignac number, because 5022525345433 - 229 = 5021988474521 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5022525345433.

It is not a weakly prime, because it can be changed into another prime (5022525345413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2511262672716 + 2511262672717.

It is an arithmetic number, because the mean of its divisors is an integer number (2511262672717).

Almost surely, 25022525345433 is an apocalyptic number.

It is an amenable number.

5022525345433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5022525345433 is an equidigital number, since it uses as much as digits as its factorization.

5022525345433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160000, while the sum is 43.

The spelling of 5022525345433 in words is "five trillion, twenty-two billion, five hundred twenty-five million, three hundred forty-five thousand, four hundred thirty-three".