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50243113411 = 471069002413
BaseRepresentation
bin101110110010101110…
…010001000111000011
311210200112021121112021
4232302232101013003
51310344214112121
635025324142311
73426033263131
oct566256210703
9153615247467
1050243113411
111a342a22827
1298a2397997
134979240a0a
142608b36751
151490db8641
hexbb2b911c3

50243113411 has 4 divisors (see below), whose sum is σ = 51312115872. Its totient is φ = 49174110952.

The previous prime is 50243113399. The next prime is 50243113447. The reversal of 50243113411 is 11431134205.

50243113411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50243113411 - 231 = 48095629763 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50243113111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 534501160 + ... + 534501253.

It is an arithmetic number, because the mean of its divisors is an integer number (12828028968).

Almost surely, 250243113411 is an apocalyptic number.

50243113411 is a deficient number, since it is larger than the sum of its proper divisors (1069002461).

50243113411 is a wasteful number, since it uses less digits than its factorization.

50243113411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1069002460.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 50243113411 its reverse (11431134205), we get a palindrome (61674247616).

The spelling of 50243113411 in words is "fifty billion, two hundred forty-three million, one hundred thirteen thousand, four hundred eleven".

Divisors: 1 47 1069002413 50243113411