Base | Representation |
---|---|
bin | 100100100100000000000… |
… | …0001111001100110101011 |
3 | 122210101200201012210220011 |
4 | 1021020000001321212223 |
5 | 1124312412213000121 |
6 | 14404301002512351 |
7 | 1026023652142423 |
oct | 111100001714653 |
9 | 18711621183804 |
10 | 5025112234411 |
11 | 16681579409a5 |
12 | 691a97b056b7 |
13 | 2a5b34935b79 |
14 | 1353069c7483 |
15 | 8aaac1b37e1 |
hex | 492000799ab |
5025112234411 has 2 divisors, whose sum is σ = 5025112234412. Its totient is φ = 5025112234410.
The previous prime is 5025112234397. The next prime is 5025112234463. The reversal of 5025112234411 is 1144322115205.
5025112234411 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5025112234411 - 213 = 5025112226219 is a prime.
It is a super-2 number, since 2×50251122344112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5025112234211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2512556117205 + 2512556117206.
It is an arithmetic number, because the mean of its divisors is an integer number (2512556117206).
Almost surely, 25025112234411 is an apocalyptic number.
5025112234411 is a deficient number, since it is larger than the sum of its proper divisors (1).
5025112234411 is an equidigital number, since it uses as much as digits as its factorization.
5025112234411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 5025112234411 its reverse (1144322115205), we get a palindrome (6169434349616).
The spelling of 5025112234411 in words is "five trillion, twenty-five billion, one hundred twelve million, two hundred thirty-four thousand, four hundred eleven".
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