Base | Representation |
---|---|
bin | 100100100100000000000… |
… | …1111000111110010011001 |
3 | 122210101200221201220022021 |
4 | 1021020000033013302121 |
5 | 1124312414104403002 |
6 | 14404301205054441 |
7 | 1026024023456323 |
oct | 111100017076231 |
9 | 18711627656267 |
10 | 5025115700377 |
11 | 1668159898a33 |
12 | 691a990b7421 |
13 | 2a5b3557a636 |
14 | 13530724a613 |
15 | 8aaac64a737 |
hex | 492003c7c99 |
5025115700377 has 2 divisors, whose sum is σ = 5025115700378. Its totient is φ = 5025115700376.
The previous prime is 5025115700251. The next prime is 5025115700401. The reversal of 5025115700377 is 7730075115205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4648762897801 + 376352802576 = 2156099^2 + 613476^2 .
It is a cyclic number.
It is not a de Polignac number, because 5025115700377 - 211 = 5025115698329 is a prime.
It is not a weakly prime, because it can be changed into another prime (5025115770377) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2512557850188 + 2512557850189.
It is an arithmetic number, because the mean of its divisors is an integer number (2512557850189).
Almost surely, 25025115700377 is an apocalyptic number.
It is an amenable number.
5025115700377 is a deficient number, since it is larger than the sum of its proper divisors (1).
5025115700377 is an equidigital number, since it uses as much as digits as its factorization.
5025115700377 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 257250, while the sum is 43.
The spelling of 5025115700377 in words is "five trillion, twenty-five billion, one hundred fifteen million, seven hundred thousand, three hundred seventy-seven".
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