Search a number
-
+
502541300273513 is a prime number
BaseRepresentation
bin111001001000011110000001…
…1101100000001000101101001
32102220100110221021101111001212
41302100330003230001011221
51011332114040332223023
64540452141454122505
7210565260621033104
oct16220740354010551
92386313837344055
10502541300273513
111361416288638a6
1248443a547b0435
131875459762a997
148c151b328d73b
153d173bc23be78
hex1c90f03b01169

502541300273513 has 2 divisors, whose sum is σ = 502541300273514. Its totient is φ = 502541300273512.

The previous prime is 502541300273503. The next prime is 502541300273527. The reversal of 502541300273513 is 315372003145205.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 368456202115369 + 134085098158144 = 19195213^2 + 11579512^2 .

It is a cyclic number.

It is not a de Polignac number, because 502541300273513 - 216 = 502541300207977 is a prime.

It is a super-2 number, since 2×5025413002735132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (502541300273503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251270650136756 + 251270650136757.

It is an arithmetic number, because the mean of its divisors is an integer number (251270650136757).

Almost surely, 2502541300273513 is an apocalyptic number.

It is an amenable number.

502541300273513 is a deficient number, since it is larger than the sum of its proper divisors (1).

502541300273513 is an equidigital number, since it uses as much as digits as its factorization.

502541300273513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378000, while the sum is 41.

The spelling of 502541300273513 in words is "five hundred two trillion, five hundred forty-one billion, three hundred million, two hundred seventy-three thousand, five hundred thirteen".