Base | Representation |
---|---|
bin | 100100100100001001100… |
… | …0111010111001100101011 |
3 | 122210102112000201121101212 |
4 | 1021020103013113030223 |
5 | 1124314041200332301 |
6 | 14404352441503335 |
7 | 1026034620610343 |
oct | 111102307271453 |
9 | 18712460647355 |
10 | 5025432433451 |
11 | 1668301661201 |
12 | 691b671a1b4b |
13 | 2a5b86086861 |
14 | 135337337d23 |
15 | 8aaca3624bb |
hex | 492131d732b |
5025432433451 has 2 divisors, whose sum is σ = 5025432433452. Its totient is φ = 5025432433450.
The previous prime is 5025432433393. The next prime is 5025432433493. The reversal of 5025432433451 is 1543342345205.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5025432433451 - 26 = 5025432433387 is a prime.
It is a super-2 number, since 2×50254324334512 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5025432433399 and 5025432433408.
It is not a weakly prime, because it can be changed into another prime (5025432403451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2512716216725 + 2512716216726.
It is an arithmetic number, because the mean of its divisors is an integer number (2512716216726).
Almost surely, 25025432433451 is an apocalyptic number.
5025432433451 is a deficient number, since it is larger than the sum of its proper divisors (1).
5025432433451 is an equidigital number, since it uses as much as digits as its factorization.
5025432433451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 41.
Adding to 5025432433451 its reverse (1543342345205), we get a palindrome (6568774778656).
The spelling of 5025432433451 in words is "five trillion, twenty-five billion, four hundred thirty-two million, four hundred thirty-three thousand, four hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.097 sec. • engine limits •