Base | Representation |
---|---|
bin | 10110110110100111010001… |
… | …11011011111001111001001 |
3 | 20120221100000010012101011011 |
4 | 23123103220323133033021 |
5 | 23041334242432144003 |
6 | 254514501230003521 |
7 | 13404543242442001 |
oct | 1333235073371711 |
9 | 216840003171134 |
10 | 50255025271753 |
11 | 15016044690395 |
12 | 57779163465a1 |
13 | 220704a94b543 |
14 | c5a4db5b9001 |
15 | 5c23adc2346d |
hex | 2db4e8edf3c9 |
50255025271753 has 2 divisors, whose sum is σ = 50255025271754. Its totient is φ = 50255025271752.
The previous prime is 50255025271699. The next prime is 50255025271757. The reversal of 50255025271753 is 35717252055205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30967355188224 + 19287670083529 = 5564832^2 + 4391773^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50255025271753 is a prime.
It is a super-3 number, since 3×502550252717533 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50255025271697 and 50255025271706.
It is not a weakly prime, because it can be changed into another prime (50255025271757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25127512635876 + 25127512635877.
It is an arithmetic number, because the mean of its divisors is an integer number (25127512635877).
Almost surely, 250255025271753 is an apocalyptic number.
It is an amenable number.
50255025271753 is a deficient number, since it is larger than the sum of its proper divisors (1).
50255025271753 is an equidigital number, since it uses as much as digits as its factorization.
50255025271753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3675000, while the sum is 49.
The spelling of 50255025271753 in words is "fifty trillion, two hundred fifty-five billion, twenty-five million, two hundred seventy-one thousand, seven hundred fifty-three".
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