503124430503341 has 4 divisors (see below), whose sum is σ = 503124480980892. Its totient is φ = 503124380025792.

The previous prime is 503124430503269. The next prime is 503124430503349. The reversal of 503124430503341 is 143305034421305.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 225068105152900 + 278056325350441 = 15002270^2 + 16675021^2 .

It is a cyclic number.

It is not a de Polignac number, because 503124430503341 - 2¹⁴ = 503124430486957 is a prime.

It is a super-2 number, since 2×503124430503341² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 503124430503295 and 503124430503304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (503124430503349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4736030 + ... + 32073023.

It is an arithmetic number, because the mean of its divisors is an integer number (125781120245223).

Almost surely, 2^{503124430503341} is an apocalyptic number.

It is an amenable number.

503124430503341 is a deficient number, since it is larger than the sum of its proper divisors (50477551).

503124430503341 is a wasteful number, since it uses less digits than its factorization.

503124430503341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50477550.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 503124430503341 its reverse (143305034421305), we get a palindrome (646429464924646).

The spelling of 503124430503341 in words is "five hundred three trillion, one hundred twenty-four billion, four hundred thirty million, five hundred three thousand, three hundred forty-one".