Base | Representation |
---|---|
bin | 10110111000100010111110… |
… | …00010111011101001000001 |
3 | 20121011200102002010110012101 |
4 | 23130101133002323221001 |
5 | 23043431242422202113 |
6 | 255005202500430401 |
7 | 13412413660544551 |
oct | 1334213702735101 |
9 | 217150362113171 |
10 | 50321431444033 |
11 | 1504122119a502 |
12 | 57887696a8401 |
13 | 22103a16672c9 |
14 | c5d7dabab161 |
15 | 5c3e98a912dd |
hex | 2dc45f0bba41 |
50321431444033 has 2 divisors, whose sum is σ = 50321431444034. Its totient is φ = 50321431444032.
The previous prime is 50321431444001. The next prime is 50321431444051. The reversal of 50321431444033 is 33044413412305.
50321431444033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48759048941824 + 1562382502209 = 6982768^2 + 1249953^2 .
It is a cyclic number.
It is not a de Polignac number, because 50321431444033 - 25 = 50321431444001 is a prime.
It is a super-2 number, since 2×503214314440332 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50321431443983 and 50321431444001.
It is not a weakly prime, because it can be changed into another prime (50321431444073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25160715722016 + 25160715722017.
It is an arithmetic number, because the mean of its divisors is an integer number (25160715722017).
Almost surely, 250321431444033 is an apocalyptic number.
It is an amenable number.
50321431444033 is a deficient number, since it is larger than the sum of its proper divisors (1).
50321431444033 is an equidigital number, since it uses as much as digits as its factorization.
50321431444033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 37.
Adding to 50321431444033 its reverse (33044413412305), we get a palindrome (83365844856338).
The spelling of 50321431444033 in words is "fifty trillion, three hundred twenty-one billion, four hundred thirty-one million, four hundred forty-four thousand, thirty-three".
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