5032440131 has 2 divisors, whose sum is σ = 5032440132. Its totient is φ = 5032440130.

The previous prime is 5032440031. The next prime is 5032440137. The reversal of 5032440131 is 1310442305.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5032440131 is a prime.

It is a super-2 number, since 2×5032440131² = 50650907344198594322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5032440097 and 5032440106.

It is not a weakly prime, because it can be changed into another prime (5032440137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516220065 + 2516220066.

It is an arithmetic number, because the mean of its divisors is an integer number (2516220066).

Almost surely, 2^5032440131 is an apocalyptic number.

5032440131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5032440131 is an equidigital number, since it uses as much as digits as its factorization.

5032440131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 5032440131 is about 70939.6936207086. The cubic root of 5032440131 is about 1713.6661004555. Note that the first 3 decimals are identical.

Adding to 5032440131 its reverse (1310442305), we get a palindrome (6342882436).

The spelling of 5032440131 in words is "five billion, thirty-two million, four hundred forty thousand, one hundred thirty-one".